10=16t^2+64t+18

Solution for 10=16t^2+64t+18 equation:

10=16t^2+64t+18

We move all terms to the left:

10-(16t^2+64t+18)=0

We get rid of parentheses

-16t^2-64t-18+10=0

We add all the numbers together, and all the variables

-16t^2-64t-8=0

a = -16; b = -64; c = -8;
Δ = b2-4ac
Δ = -642-4·(-16)·(-8)
Δ = 3584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3584}=\sqrt{256*14}=\sqrt{256}*\sqrt{14}=16\sqrt{14}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-16\sqrt{14}}{2*-16}=\frac{64-16\sqrt{14}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+16\sqrt{14}}{2*-16}=\frac{64+16\sqrt{14}}{-32}
$